Conditional Logic with “how satisfied” table

Hello!

The survey support in formulas and conditionals logis is still pretty basic, could you tell me what would you like to do?

It is possible but since the support is very basic it is still difficult to create conditions that use the survey table.

For example, if you have the default survey table (the table that is created when you drag the survey field into your form). You could create a ‘Formula’ conditional logic (section 3 of this tutorial:https://sfmanual.rednao.com/documentation/conditional-logic/doing-calculations-in-conditional-logics/) that display a field only when the ‘Support’ question is rated as ‘Very Satisfied’ like this:

var values=$$field_rnField3$$.OriginalValues.values;
for(var i=0;i<values.length;i++){
if(values[i].QuestionLabel=='Support'&&values[i].ValueLabel=='Very Satisfied')
	return true;  
}
return false;

In the code bellow i am basically searching for the ‘Support’ question in my survey and checking if it was rated as ‘Very Satisfied’ if so i am returning ‘true’ which will trigger the conditional logic and would show the field that i configured.

Regards!