Facultary n!

  • Resolved digiblogger

    (@digiblogger)


    6 years, 11 months ago

    Assuming you want to know: How many different combinations will i get, when I choose k elements from an amount of n total elements.

    the formular is:

    n!/(n-k)!*k!

    I am looking for a way to translate this into CFF Pro 🙂 Thanks.

    • This topic was modified 6 years, 11 months ago by digiblogger.
Viewing 2 replies - 1 through 2 (of 2 total)
  • Thread Starter digiblogger

    (@digiblogger)

    6 years, 11 months ago

    I already wrote an email 🙂 I really think I need help to implement

    n!/(n-k)!*k!

    Thread Starter digiblogger

    (@digiblogger)

    6 years, 11 months ago

    did on my own.

    For all:

    Insert a html field with this code:

    <script>
function factorial(n) {
  return (n != 1) ? n * factorial(n - 1) : 1;
}
</script>

    Not you can use factorial(YourFieldname)

    • This reply was modified 6 years, 11 months ago by digiblogger.
Viewing 2 replies - 1 through 2 (of 2 total)

The topic ‘Facultary n!’ is closed to new replies.

Tags